Astron. Astrophys. 364, L89-L92 (2000)
2. Strange stars at finite temperatures
The interesting point made in D98 is that starting from an
empirical form for the density dependent masses of the up (u), down
(d) and strange (s) q-s given below one can constrain the parametric
form of this mass from recent astronomical
data 1:
![[EQUATION]](img8.gif)
Restoration of chiral quark masses at high density is incorporated
in this model. Using the model parameter
( ) for this restoration one can
calculate the density dependence of the strong coupling constant (Ray
et al. 2000b). In other words the masses of stars in units of solar
mass, ( ), found as a function of the
star radius R, calculated using the above Eq. 1, -
produces constraints which enable us to restrict the parameter
. At high
the q- mass
falls from its constituent value
to its current one
. The parameter
is taken to be 310 MeV to match up
with constituent q- masses assuming the known fact that the hadrons
have very little potential energy. The results are not very sensitive
in so far as changing to 320 MeV
changes the maximum mass of the star from 1.43735
to 1.43738
and the corresponding radius changes
from 7.0553 kms to 7.0558 kms.
It is interesting to plot the up (u), down (d) and strange (s) q-
masses at various radii in a star. This is done with strong coupling
constant , chiral symmetry
restoration parameter and the QCD
scale parameter already discussed in
D98 & Li et al. (1999a,b). Fig. 1 shows that the quarks do
not have the constituent masses as in zero density hadrons nor do they
have the current masses of the bag model. Upto a radius about 2 kms
the quarks have their chiral current mass but in the major portion of
the star their masses are substantially higher. At the surface the
strange q- mass is about 278 MeV and the u, d q- masses
MeV.
![[FIGURE]](img18.gif) |
Fig. 1. The smooth restoration of chiral symmetry inside the star for each of the u, d and s flavours (note that this is for the zero temperature result).
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We use the large (colour)
approximation of 't Hooft (1974) for quarks, where quark loops are
suppressed by and the calculation
can be performed at the tree level with a mean field derived from a qq
interaction (Witten 1979). This was done for baryons (Dey et al. 1986;
Dey et al. 1991; Ray et al. 2000a) and extended to dense systems like
stars (D98). Following is the Hamiltonian, with a two-body potential
:
![[EQUATION]](img23.gif)
The vector potential in Eq. 2 between quarks originate from
gluon exchanges, and the -s are the
color SU(3) matrices for the two interacting quarks. In the absence of
an accurate evaluation of the potential (e.g. from large
planar diagrams) we borrow it from
meson phenomenology, namely the Richardson potential (Richardson
1979). The potential reproduces heavy as well as light meson spectra
(Crater et al. 1984). It has been well tested for baryons in Fock
calculations (Dey et al. 1986; Dey et al. 1991). Recently, using the
Vlasov approach with the Richardson potential, Bonasera (1999) finds a
transition from nuclear to quark matter at densities 5 times
.
We had to calculate the potential energy (PE) contribution in two
steps: the single particle potential,
, for momentum k, is first
calculated and this is subsequently integrated to get the PE. The
is needed for doing finite T
calculation.
The is parametrized as sum of
exponentials in k (i.e., for
a given flavour), where the parameters for a given set, reported in
this paper, with ,
MeV,
and a typical density
are given in Table 1.
![[TABLE]](img33.gif)
Table 1. Parameters of ![[FORMULA]](img31.gif)
Finite temperature can be
incorporated in the system through the Fermi function:
![[EQUATION]](img35.gif)
with the flavour dependent single particle energy
![[EQUATION]](img36.gif)
Now we evaluate
![[EQUATION]](img37.gif)
For we get the number density and
for , the energy density.
is the spin-colour degeneracy.
Even at very high T which is around 70 MeV, the chemical
potential is very large, of the order several hundred MeV. The entropy
is calculated as follows:
![[EQUATION]](img41.gif)
![[EQUATION]](img42.gif)
The pressure (P) is calculated from the free energy
![[EQUATION]](img43.gif)
as follows:
![[EQUATION]](img44.gif)
We find P = 0 points only upto T = 70 MeV on plotting
P as a function of at
different T (Fig. 2).
![[FIGURE]](img46.gif) |
Fig. 2. The equation of states for different T. It is to be noted that beyond T = 70 MeV, the zero of the pressure cannot be attained.
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© European Southern Observatory (ESO) 2000
Online publication: January 29, 2001
helpdesk.link@springer.de  |